What are the solutions to the equation 33x^4-8x^2+4=0 ?

The solutions to the equation 33x^4-8x^2+4=0 are

Find the zeros of 33x^4-8x^2+4=0

The zeros of 33x^4-8x^2+4=0 are

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

33 x^{4} - 8 x^{2} + 4 = 0

x = \frac{2 + 33}{33} + \frac{29}{33 \frac{2 + 33}{33}} i, x = - \frac{2 + 33}{33} - \frac{29}{33 2 + 33} i, x = \frac{2 + 33}{33} - \frac{29}{33 2 + 33} i, x = - \frac{2 + 33}{33} + \frac{29}{33 2 + 33} i

Solution steps

33 x^{4} - 8 x^{2} + 4 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

33 u^{2} - 8 u + 4 = 0

Solve

33 u^{2} - 8 u + 4 = 0 : u = \frac{4}{33} + i \frac{2 29}{33}, u = \frac{4}{33} - i \frac{2 29}{33}

u = \frac{4}{33} + i \frac{2 29}{33}, u = \frac{4}{33} - i \frac{2 29}{33}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{4}{33} + i \frac{2 29}{33} : x = \frac{2 + 33}{33} + \frac{29}{33 \frac{2 + 33}{33}} i, x = - \frac{2 + 33}{33} - \frac{29}{33 2 + 33} i

Solve

x^{2} = \frac{4}{33} - i \frac{2 29}{33} : x = \frac{2 + 33}{33} - \frac{29}{33 2 + 33} i, x = - \frac{2 + 33}{33} + \frac{29}{33 2 + 33} i

The solutions are

x = \frac{2 + 33}{33} + \frac{29}{33 \frac{2 + 33}{33}} i, x = - \frac{2 + 33}{33} - \frac{29}{33 2 + 33} i, x = \frac{2 + 33}{33} - \frac{29}{33 2 + 33} i, x = - \frac{2 + 33}{33} + \frac{29}{33 2 + 33} i

(x) = (x^{3} + 8) \cdot (3 x - 15)

(x + 1)^{5} = \frac{1}{32}

(x + 2)^{2} \cdot (x + 6)^{3} + (x + 2) \cdot (x + 6)^{4} = 0

x^{6} = 5

(3 x - 2) (x^{1}) - (2 x^{3}) (2 - x) = 182 x

What are the solutions to the equation 33x^4-8x^2+4=0 ?
The solutions to the equation 33x^4-8x^2+4=0 are
Find the zeros of 33x^4-8x^2+4=0
The zeros of 33x^4-8x^2+4=0 are