What are the solutions to the equation (x^2-3x)^2-16(x^2-3x)-36=0 ?

The solutions to the equation (x^2-3x)^2-16(x^2-3x)-36=0 are x=1,x=2,x=-3,x=6

Find the zeros of (x^2-3x)^2-16(x^2-3x)-36=0

The zeros of (x^2-3x)^2-16(x^2-3x)-36=0 are x=1,x=2,x=-3,x=6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} - 3 x)^{2} - 16 (x^{2} - 3 x) - 36 = 0

x = 1, x = 2, x = - 3, x = 6

Solution steps

(x^{2} - 3 x)^{2} - 16 (x^{2} - 3 x) - 36 = 0

Expand

(x^{2} - 3 x)^{2} - 16 (x^{2} - 3 x) - 36 : x^{4} - 6 x^{3} - 7 x^{2} + 48 x - 36

x^{4} - 6 x^{3} - 7 x^{2} + 48 x - 36 = 0

Factor

x^{4} - 6 x^{3} - 7 x^{2} + 48 x - 36 : (x - 1) (x - 2) (x + 3) (x - 6)

(x - 1) (x - 2) (x + 3) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 2 = 0 or x + 3 = 0 or x - 6 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 6 = 0 : x = 6

The solutions are

x = 1, x = 2, x = - 3, x = 6

x^{3} - x = 1

x^{4} + 5 x^{2} + 4 = 0

(x + 4)^{3} = - 729

5 x^{3} - 4 x^{2} + 4 x = 0

z^{6} + z^{3} + 1 = 0

What are the solutions to the equation (x^2-3x)^2-16(x^2-3x)-36=0 ?
The solutions to the equation (x^2-3x)^2-16(x^2-3x)-36=0 are x=1,x=2,x=-3,x=6
Find the zeros of (x^2-3x)^2-16(x^2-3x)-36=0
The zeros of (x^2-3x)^2-16(x^2-3x)-36=0 are x=1,x=2,x=-3,x=6