What are the solutions to the equation 3x^3+7x^2+17x+5=0 ?

The solutions to the equation 3x^3+7x^2+17x+5=0 are x=-1/3 ,x=-1+2i,x=-1-2i

Find the zeros of 3x^3+7x^2+17x+5=0

The zeros of 3x^3+7x^2+17x+5=0 are x=-1/3 ,x=-1+2i,x=-1-2i

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3 x^{3} + 7 x^{2} + 17 x + 5 = 0

x = - \frac{1}{3}, x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

3 x^{3} + 7 x^{2} + 17 x + 5 = 0

Factor

3 x^{3} + 7 x^{2} + 17 x + 5 : (3 x + 1) (x^{2} + 2 x + 5)

(3 x + 1) (x^{2} + 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or x^{2} + 2 x + 5 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

x^{2} + 2 x + 5 = 0 : x = - 1 + 2 i, x = - 1 - 2 i

The solutions are

x = - \frac{1}{3}, x = - 1 + 2 i, x = - 1 - 2 i

3 x^{3} + 6 x - 21 x^{2} - 42 = 0

\frac{x ^{8} + 1}{( 2 c ^{4} )} = 98

7 a^{3} + 41 - a^{3} = - 52

1 - 3 \cdot (x + 4)^{3} = 25

(z + 1)^{4} = - 1

What are the solutions to the equation 3x^3+7x^2+17x+5=0 ?
The solutions to the equation 3x^3+7x^2+17x+5=0 are x=-1/3 ,x=-1+2i,x=-1-2i
Find the zeros of 3x^3+7x^2+17x+5=0
The zeros of 3x^3+7x^2+17x+5=0 are x=-1/3 ,x=-1+2i,x=-1-2i