What are the solutions to the equation x^3-5x^2=36x ?

The solutions to the equation x^3-5x^2=36x are x=0,x=-4,x=9

Find the zeros of x^3-5x^2=36x

The zeros of x^3-5x^2=36x are x=0,x=-4,x=9

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x^{3} - 5 x^{2} = 36 x

x = 0, x = - 4, x = 9

Solution steps

x^{3} - 5 x^{2} = 36 x

Move

36 x

to the left side

x^{3} - 5 x^{2} - 36 x = 0

Factor

x^{3} - 5 x^{2} - 36 x : x (x + 4) (x - 9)

x (x + 4) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0 or x - 9 = 0

Solve

x + 4 = 0 : x = - 4

Solve

x - 9 = 0 : x = 9

The solutions are

x = 0, x = - 4, x = 9

81 = a^{4}

a, 55 \cdot a^{3} = 22 \cdot b^{3}

x^{4} - 2 x^{2} - 3 = 0

x (2 x + 0.25)^{2} = 5.16 \cdot 1 0^{- 1} 1

c^{6} - 36 c^{4} = 0

What are the solutions to the equation x^3-5x^2=36x ?
The solutions to the equation x^3-5x^2=36x are x=0,x=-4,x=9
Find the zeros of x^3-5x^2=36x
The zeros of x^3-5x^2=36x are x=0,x=-4,x=9