What are the solutions to the equation 5x^2-16x+12=0 ?

The solutions to the equation 5x^2-16x+12=0 are x=2,x= 6/5

Find the zeros of 5x^2-16x+12=0

The zeros of 5x^2-16x+12=0 are x=2,x= 6/5

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5 x^{2} - 16 x + 12 = 0

x = 2, x = \frac{6}{5}

Solution steps

5 x^{2} - 16 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 5 \cdot 12}{2 \cdot 5}

(- 16)^{2} - 4 \cdot 5 \cdot 12 = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 5}, x_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 5}

x = \frac{- ( - 16 ) + 4}{2 \cdot 5} : 2

x = \frac{- ( - 16 ) - 4}{2 \cdot 5} : \frac{6}{5}

The solutions to the quadratic equation are:

x = 2, x = \frac{6}{5}

\frac{3}{4} - \frac{1}{28}

70 = x + 42

- 11 x + 3 (x - 8) \geq 3 x - (8 + 2 x) - 61

\frac{3 !}{3 ! 0 !}

x^{2} x^{- 2}

What are the solutions to the equation 5x^2-16x+12=0 ?
The solutions to the equation 5x^2-16x+12=0 are x=2,x= 6/5
Find the zeros of 5x^2-16x+12=0
The zeros of 5x^2-16x+12=0 are x=2,x= 6/5