What are the solutions to the equation solvefor n,p=(n^2)+1 ?

The solutions to the equation solvefor n,p=(n^2)+1 are n=sqrt(p-1),n=-sqrt(p-1)

Find the zeros of solvefor n,p=(n^2)+1

The zeros of solvefor n,p=(n^2)+1 are n=sqrt(p-1),n=-sqrt(p-1)

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solve for

n, p = (n^{2}) + 1

n = p - 1, n = - p - 1

Solution steps

p = (n^{2}) + 1

Refine

p = n^{2} + 1

Switch sides

n^{2} + 1 = p

Move

1

to the right side

n^{2} = p - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = p - 1, n = - p - 1

(\frac{x + 1}{3}) (\frac{x - 1}{3}) = \frac{1}{3}

x, z = 5 x_{3} x^{2} y^{+} 7 y^{5}

x^{3} - 4 x^{2} - x + 1 = (x - 2)^{3}

x, y^{2} - 1 = (x - 1) (x - 3)

y^{2} + 9 y - 10 = 0

What are the solutions to the equation solvefor n,p=(n^2)+1 ?
The solutions to the equation solvefor n,p=(n^2)+1 are n=sqrt(p-1),n=-sqrt(p-1)
Find the zeros of solvefor n,p=(n^2)+1
The zeros of solvefor n,p=(n^2)+1 are n=sqrt(p-1),n=-sqrt(p-1)