What are the solutions to the equation x^2+0.9x-0.36=0 ?

The solutions to the equation x^2+0.9x-0.36=0 are x= 3/10 ,x=-6/5

Find the zeros of x^2+0.9x-0.36=0

The zeros of x^2+0.9x-0.36=0 are x= 3/10 ,x=-6/5

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x^{2} + 0.9 x - 0.36 = 0

x = \frac{3}{10}, x = - \frac{6}{5}

Decimal Notation

x = 0.3, x = - 1.2

Solution steps

x^{2} + 0.9 x - 0.36 = 0

Multiply both sides by

100

100 x^{2} + 90 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 \cdot 100 ( - 36 )}{2 \cdot 100}

9 0^{2} - 4 \cdot 100 (- 36) = 150

x_{1, 2} = \frac{- 90 \pm 150}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 90 + 150}{2 \cdot 100}, x_{2} = \frac{- 90 - 150}{2 \cdot 100}

x = \frac{- 90 + 150}{2 \cdot 100} : \frac{3}{10}

x = \frac{- 90 - 150}{2 \cdot 100} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{3}{10}, x = - \frac{6}{5}

x, z (x + y) p + z (x - y) q = x^{2} + y^{2}

(\frac{1}{2}) a (a - 18) = 2480

n (t) = 15 t^{2} - 180 t + 5000

6 x^{2} + (a - 12) x - (a^{2} + a - 6) = 0

4 x^{2} - 4 a^{2} x + (a^{4} - b^{4}) = 0

What are the solutions to the equation x^2+0.9x-0.36=0 ?
The solutions to the equation x^2+0.9x-0.36=0 are x= 3/10 ,x=-6/5
Find the zeros of x^2+0.9x-0.36=0
The zeros of x^2+0.9x-0.36=0 are x= 3/10 ,x=-6/5