What are the solutions to the equation x^2-5x+6=2-3 ?

The solutions to the equation x^2-5x+6=2-3 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2

Find the zeros of x^2-5x+6=2-3

The zeros of x^2-5x+6=2-3 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2

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x^{2} - 5 x + 6 = 2 - 3

x = \frac{5}{2} + i \frac{3}{2}, x = \frac{5}{2} - i \frac{3}{2}

Solution steps

x^{2} - 5 x + 6 = 2 - 3

Refine

x^{2} - 5 x + 6 = - 1

Move

1

to the left side

x^{2} - 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 7 : 3 i

x_{1, 2} = \frac{- ( - 5 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3 i}{2 \cdot 1} : \frac{5}{2} + i \frac{3}{2}

x = \frac{- ( - 5 ) - 3 i}{2 \cdot 1} : \frac{5}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{3}{2}, x = \frac{5}{2} - i \frac{3}{2}

x^{2} - (1 + 2) \cdot x + 2 = 0

\frac{( x ^{2} )}{6} - \frac{( 3 x )}{6} = 3 (x - 5)

4 x^{2} - 4 a^{2} \cdot x + (a^{4} - b^{4}) = 0

x, x^{2} - 10 x + y^{2} - 20 y = - 125

x, z = (5 x + 3) (6 x + 2 y)

What are the solutions to the equation x^2-5x+6=2-3 ?
The solutions to the equation x^2-5x+6=2-3 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2
Find the zeros of x^2-5x+6=2-3
The zeros of x^2-5x+6=2-3 are x= 5/2+i(sqrt(3))/2 ,x= 5/2-i(sqrt(3))/2