What are the solutions to the equation x^2+1.2x=0 ?

The solutions to the equation x^2+1.2x=0 are x=0,x=-1.2

Find the zeros of x^2+1.2x=0

The zeros of x^2+1.2x=0 are x=0,x=-1.2

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x^{2} + 1.2 x = 0

x = 0, x = - 1.2

Solution steps

x^{2} + 1.2 x = 0

Factor

x^{2} + 1.2 x : x (x + 1.2)

x (x + 1.2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1.2 = 0

Solve

x + 1.2 = 0 : x = - 1.2

The solutions to the quadratic equation are:

x = 0, x = - 1.2

x, z = f (x^{2} + y^{2})

x, x^{2} + y^{2} + 4 z^{2} - 6 x - 2 y - 4 z + 11 = 0

a, a^{2} + b^{2} + 8 a - 14 b + 65 = 0

x^{2} - x - a (a + 1) = 0

6 x^{2} - 9 x + 12 = 0

What are the solutions to the equation x^2+1.2x=0 ?
The solutions to the equation x^2+1.2x=0 are x=0,x=-1.2
Find the zeros of x^2+1.2x=0
The zeros of x^2+1.2x=0 are x=0,x=-1.2