What are the solutions to the equation 0.8x-1=1.5x^2 ?

The solutions to the equation 0.8x-1=1.5x^2 are x= 4/15+i(sqrt(134))/(15),x= 4/15-i(sqrt(134))/(15)

Find the zeros of 0.8x-1=1.5x^2

The zeros of 0.8x-1=1.5x^2 are x= 4/15+i(sqrt(134))/(15),x= 4/15-i(sqrt(134))/(15)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0.8 x - 1 = 1.5 x^{2}

x = \frac{4}{15} + i \frac{134}{15}, x = \frac{4}{15} - i \frac{134}{15}

Solution steps

0.8 x - 1 = 1.5 x^{2}

Multiply both sides by

10

8 x - 10 = 15 x^{2}

Switch sides

15 x^{2} = 8 x - 10

Move

10

to the left side

15 x^{2} + 10 = 8 x

Move

8 x

to the left side

15 x^{2} + 10 - 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

15 x^{2} - 8 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 15 \cdot 10}{2 \cdot 15}

Simplify

(- 8)^{2} - 4 \cdot 15 \cdot 10 : 2134 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 134 i}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 134 i}{2 \cdot 15}, x_{2} = \frac{- ( - 8 ) - 2 134 i}{2 \cdot 15}

x = \frac{- ( - 8 ) + 2 134 i}{2 \cdot 15} : \frac{4}{15} + i \frac{134}{15}

x = \frac{- ( - 8 ) - 2 134 i}{2 \cdot 15} : \frac{4}{15} - i \frac{134}{15}

The solutions to the quadratic equation are:

x = \frac{4}{15} + i \frac{134}{15}, x = \frac{4}{15} - i \frac{134}{15}

x, x^{2} - 2 x y - 2 y^{2} = - x^{2} - 2 x y - y^{2}

x^{2} - 12 x = 28

x, g = x^{2} - x - 2 g (3)

20 m^{2} + 7 m - 6 = 0

9 x = (0.5 x^{2}) + 40

What are the solutions to the equation 0.8x-1=1.5x^2 ?
The solutions to the equation 0.8x-1=1.5x^2 are x= 4/15+i(sqrt(134))/(15),x= 4/15-i(sqrt(134))/(15)
Find the zeros of 0.8x-1=1.5x^2
The zeros of 0.8x-1=1.5x^2 are x= 4/15+i(sqrt(134))/(15),x= 4/15-i(sqrt(134))/(15)