What are the solutions to the equation 3*(x+2)^2=48 ?

The solutions to the equation 3*(x+2)^2=48 are x=2,x=-6

Find the zeros of 3*(x+2)^2=48

The zeros of 3*(x+2)^2=48 are x=2,x=-6

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3 \cdot (x + 2)^{2} = 48

x = 2, x = - 6

Solution steps

3 (x + 2)^{2} = 48

Divide both sides by

3

(x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

a, m (a) = 8 a^{2} + 15 a - 10

x^{2} + (\frac{a + 1}{a}) x + 1 = 0

x^{2} + 8 x - 1920 = 0

y, y^{2} = x^{5} (2 a - x)

x, p \cdot x^{2} - (3 p + 2) \cdot x + (5 p - 2) = 0

What are the solutions to the equation 3*(x+2)^2=48 ?
The solutions to the equation 3*(x+2)^2=48 are x=2,x=-6
Find the zeros of 3*(x+2)^2=48
The zeros of 3*(x+2)^2=48 are x=2,x=-6