What are the solutions to the equation y^2-6y-12=0 ?

The solutions to the equation y^2-6y-12=0 are y=3+sqrt(21),y=3-sqrt(21)

Find the zeros of y^2-6y-12=0

The zeros of y^2-6y-12=0 are y=3+sqrt(21),y=3-sqrt(21)

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y^{2} - 6 y - 12 = 0

y = 3 + 21, y = 3 - 21

Solution steps

y^{2} - 6 y - 12 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 12) = 221

y_{1, 2} = \frac{- ( - 6 ) \pm 2 21}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 21}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2 21}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2 21}{2 \cdot 1} : 3 + 21

y = \frac{- ( - 6 ) - 2 21}{2 \cdot 1} : 3 - 21

The solutions to the quadratic equation are:

y = 3 + 21, y = 3 - 21

7 (2 n - 9) + 28 = 21

\frac{( \frac{1}{4} )}{4}

3 n^{2} + 8 n + 4

\frac{20}{7} - 12

\frac{1}{3} + \frac{3}{6} + \frac{1}{2}

What are the solutions to the equation y^2-6y-12=0 ?
The solutions to the equation y^2-6y-12=0 are y=3+sqrt(21),y=3-sqrt(21)
Find the zeros of y^2-6y-12=0
The zeros of y^2-6y-12=0 are y=3+sqrt(21),y=3-sqrt(21)