What are the solutions to the equation 3x^2+2sqrt(5)x-5=0 ?

The solutions to the equation 3x^2+2sqrt(5)x-5=0 are x=(sqrt(5))/3 ,x=-sqrt(5)

Find the zeros of 3x^2+2sqrt(5)x-5=0

The zeros of 3x^2+2sqrt(5)x-5=0 are x=(sqrt(5))/3 ,x=-sqrt(5)

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3 x^{2} + 25 x - 5 = 0

x = \frac{5}{3}, x = - 5

Decimal Notation

x = 0.74535 \dots, x = - 2.23606 \dots

Solution steps

3 x^{2} + 25 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 5 \pm ( 2 5 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(25)^{2} - 4 \cdot 3 (- 5) = 45

x_{1, 2} = \frac{- 2 5 \pm 4 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 5 + 4 5}{2 \cdot 3}, x_{2} = \frac{- 2 5 - 4 5}{2 \cdot 3}

x = \frac{- 2 5 + 4 5}{2 \cdot 3} : \frac{5}{3}

x = \frac{- 2 5 - 4 5}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 5

2 - 5 k = \frac{k ^{2}}{3}

t, a^{2} b^{2} t^{2} - a^{2} t = 1 - b^{2} t

43 \cdot x^{2} + 5 x - 23 = 0

d^{2} = 4 x^{2} - 12 x + 9

0.2 x^{2} + 1.2 x - 32 = 0

What are the solutions to the equation 3x^2+2sqrt(5)x-5=0 ?
The solutions to the equation 3x^2+2sqrt(5)x-5=0 are x=(sqrt(5))/3 ,x=-sqrt(5)
Find the zeros of 3x^2+2sqrt(5)x-5=0
The zeros of 3x^2+2sqrt(5)x-5=0 are x=(sqrt(5))/3 ,x=-sqrt(5)