What are the solutions to the equation 15x^2-28=x ?

The solutions to the equation 15x^2-28=x are x= 7/5 ,x=-4/3

Find the zeros of 15x^2-28=x

The zeros of 15x^2-28=x are x= 7/5 ,x=-4/3

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15 x^{2} - 28 = x

x = \frac{7}{5}, x = - \frac{4}{3}

Decimal Notation

x = 1.4, x = - 1.33333 \dots

Solution steps

15 x^{2} - 28 = x

Move

x

to the left side

15 x^{2} - 28 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

15 x^{2} - x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 15 ( - 28 )}{2 \cdot 15}

(- 1)^{2} - 4 \cdot 15 (- 28) = 41

x_{1, 2} = \frac{- ( - 1 ) \pm 41}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 41}{2 \cdot 15}, x_{2} = \frac{- ( - 1 ) - 41}{2 \cdot 15}

x = \frac{- ( - 1 ) + 41}{2 \cdot 15} : \frac{7}{5}

x = \frac{- ( - 1 ) - 41}{2 \cdot 15} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{7}{5}, x = - \frac{4}{3}

x, - 8 x^{2} + 18 y^{2} + 18 z^{2} = 2

t, h = \frac{1}{2} \cdot a_{g (t)} \cdot t^{2}

(7 x)^{2} - 49 = 0

- 0.1 (49 x^{2} - 920 x - 12) = 0

2 = 0.013 x^{2} - 1.18 x + 28.24

What are the solutions to the equation 15x^2-28=x ?
The solutions to the equation 15x^2-28=x are x= 7/5 ,x=-4/3
Find the zeros of 15x^2-28=x
The zeros of 15x^2-28=x are x= 7/5 ,x=-4/3