What are the solutions to the equation 4y^2-215y+2875=0 ?

The solutions to the equation 4y^2-215y+2875=0 are y= 115/4 ,y=25

Find the zeros of 4y^2-215y+2875=0

The zeros of 4y^2-215y+2875=0 are y= 115/4 ,y=25

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4 y^{2} - 215 y + 2875 = 0

y = \frac{115}{4}, y = 25

Decimal Notation

y = 28.75, y = 25

Solution steps

4 y^{2} - 215 y + 2875 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 215 ) \pm ( - 215 ) ^{2} - 4 \cdot 4 \cdot 2875}{2 \cdot 4}

(- 215)^{2} - 4 \cdot 4 \cdot 2875 = 15

y_{1, 2} = \frac{- ( - 215 ) \pm 15}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 215 ) + 15}{2 \cdot 4}, y_{2} = \frac{- ( - 215 ) - 15}{2 \cdot 4}

y = \frac{- ( - 215 ) + 15}{2 \cdot 4} : \frac{115}{4}

y = \frac{- ( - 215 ) - 15}{2 \cdot 4} : 25

The solutions to the quadratic equation are:

y = \frac{115}{4}, y = 25

x, a = x^{2} m + x^{2} n + x^{2} q

q \cdot = 5 + (- q) \cdot (q) + 10

16 x^{2} - 625 = 0

k, k^{2} = n^{2} + 3 n + 15

(x - 4)^{3} = x (x^{2} + 2 x)

What are the solutions to the equation 4y^2-215y+2875=0 ?
The solutions to the equation 4y^2-215y+2875=0 are y= 115/4 ,y=25
Find the zeros of 4y^2-215y+2875=0
The zeros of 4y^2-215y+2875=0 are y= 115/4 ,y=25