What are the solutions to the equation (2x^2)/(16)=2^3x ?

The solutions to the equation (2x^2)/(16)=2^3x are x=64,x=0

Find the zeros of (2x^2)/(16)=2^3x

The zeros of (2x^2)/(16)=2^3x are x=64,x=0

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\frac{2 x ^{2}}{16} = 2^{3} x

x = 64, x = 0

Solution steps

\frac{2 x ^{2}}{16} = 2^{3} x

Multiply both sides by

16

2 x^{2} = 2^{3} x \cdot 16

Move

2^{3} x 16

to the left side

2 x^{2} - 2^{3} x \cdot 16 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 2^{3} \cdot 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ^{3} \cdot 16 ) \pm ( - 2 ^{3} \cdot 16 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 2^{3} \cdot 16)^{2} - 4 \cdot 2 \cdot 0 = 128

x_{1, 2} = \frac{- ( - 2 ^{3} \cdot 16 ) \pm 128}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ^{3} \cdot 16 ) + 128}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ^{3} \cdot 16 ) - 128}{2 \cdot 2}

x = \frac{- ( - 2 ^{3} \cdot 16 ) + 128}{2 \cdot 2} : 64

x = \frac{- ( - 2 ^{3} \cdot 16 ) - 128}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = 64, x = 0

x, 2 f - f = x^{2}

2.2 x^{2} - 8.8 x = 0

x, x^{2} - y^{4} = 2035

(x - b) (x - c) + (x - c) (x - a) + (x - a) (x - b) = 0

x, 15 (2 x^{2} - y^{2}) = 7 x y

What are the solutions to the equation (2x^2)/(16)=2^3x ?
The solutions to the equation (2x^2)/(16)=2^3x are x=64,x=0
Find the zeros of (2x^2)/(16)=2^3x
The zeros of (2x^2)/(16)=2^3x are x=64,x=0