What are the solutions to the equation (6x+2)^2=16 ?

The solutions to the equation (6x+2)^2=16 are x= 1/3 ,x=-1

Find the zeros of (6x+2)^2=16

The zeros of (6x+2)^2=16 are x= 1/3 ,x=-1

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(6 x + 2)^{2} = 16

x = \frac{1}{3}, x = - 1

Decimal Notation

x = 0.33333 \dots, x = - 1

Solution steps

(6 x + 2)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

6 x + 2 = 16 : x = \frac{1}{3}

Solve

6 x + 2 = - 16 : x = - 1

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 1

\frac{( x + 2 ) ^{2} - ( 2 x + 11 )}{3} = 3

\frac{3}{1} + x - x^{2} + \frac{1}{1} - x^{2} + x + \frac{1}{1} - x = 0

\frac{x}{3} = \frac{x ^{2}}{5}

x^{2} + 2 a - 15 = 0

9 x^{2} - 60 x + (a^{2} + b^{2}) = 0

What are the solutions to the equation (6x+2)^2=16 ?
The solutions to the equation (6x+2)^2=16 are x= 1/3 ,x=-1
Find the zeros of (6x+2)^2=16
The zeros of (6x+2)^2=16 are x= 1/3 ,x=-1