What are the solutions to the equation x^2-25=a^2-b^2 ?

The solutions to the equation x^2-25=a^2-b^2 are x=sqrt(a^2-b^2+25),x=-sqrt(a^2-b^2+25)

Find the zeros of x^2-25=a^2-b^2

The zeros of x^2-25=a^2-b^2 are x=sqrt(a^2-b^2+25),x=-sqrt(a^2-b^2+25)

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x^{2} - 25 = a^{2} - b^{2}

x = a^{2} - b^{2} + 25, x = - a^{2} - b^{2} + 25

Solution steps

x^{2} - 25 = a^{2} - b^{2}

Move

25

to the right side

x^{2} = a^{2} - b^{2} + 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = a^{2} - b^{2} + 25, x = - a^{2} - b^{2} + 25

(m - 2) \cdot x^{2} - (3 m - 8) x + m - 9 = 0

2 - x^{2} = 2

x^{2} + a = 25

x, x^{2} + y^{2} - 4 x - 6 y + 19 = 0

3 m^{2} - 243 m = 0

What are the solutions to the equation x^2-25=a^2-b^2 ?
The solutions to the equation x^2-25=a^2-b^2 are x=sqrt(a^2-b^2+25),x=-sqrt(a^2-b^2+25)
Find the zeros of x^2-25=a^2-b^2
The zeros of x^2-25=a^2-b^2 are x=sqrt(a^2-b^2+25),x=-sqrt(a^2-b^2+25)