What are the solutions to the equation s^2+2s+5=0 ?

The solutions to the equation s^2+2s+5=0 are s=-1+2i,s=-1-2i

Find the zeros of s^2+2s+5=0

The zeros of s^2+2s+5=0 are s=-1+2i,s=-1-2i

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s^{2} + 2 s + 5 = 0

s = - 1 + 2 i, s = - 1 - 2 i

Solution steps

s^{2} + 2 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 5 : 4 i

s_{1, 2} = \frac{- 2 \pm 4 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 4 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 4 i}{2 \cdot 1}

s = \frac{- 2 + 4 i}{2 \cdot 1} : - 1 + 2 i

s = \frac{- 2 - 4 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

s = - 1 + 2 i, s = - 1 - 2 i

\frac{16}{3} - 4

4 a^{2} - 16

3 (2 x - 7) = 5 x + 17 + x

\frac{w}{2} > 44

4 X - 18 > 2

What are the solutions to the equation s^2+2s+5=0 ?
The solutions to the equation s^2+2s+5=0 are s=-1+2i,s=-1-2i
Find the zeros of s^2+2s+5=0
The zeros of s^2+2s+5=0 are s=-1+2i,s=-1-2i