What are the solutions to the equation 6sqrt(5)*x^2-9x-3sqrt(5)=0 ?

The solutions to the equation 6sqrt(5)*x^2-9x-3sqrt(5)=0 are x=(sqrt(5))/2 ,x=-1/(sqrt(5))

Find the zeros of 6sqrt(5)*x^2-9x-3sqrt(5)=0

The zeros of 6sqrt(5)*x^2-9x-3sqrt(5)=0 are x=(sqrt(5))/2 ,x=-1/(sqrt(5))

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65 \cdot x^{2} - 9 x - 35 = 0

x = \frac{5}{2}, x = - \frac{1}{5}

Decimal Notation

x = 1.11803 \dots, x = - 0.4472135955

Solution steps

65 x^{2} - 9 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 6 5 ( - 3 5 )}{2 \cdot 6 5}

(- 9)^{2} - 4 \cdot 65 (- 35) = 21

x_{1, 2} = \frac{- ( - 9 ) \pm 21}{2 \cdot 6 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 21}{2 \cdot 6 5}, x_{2} = \frac{- ( - 9 ) - 21}{2 \cdot 6 5}

x = \frac{- ( - 9 ) + 21}{2 \cdot 6 5} : \frac{5}{2}

x = \frac{- ( - 9 ) - 21}{2 \cdot 6 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{1}{5}

a^{2} \cdot x^{2} - b^{2} = 0

x, x^{2} + y^{2} + z^{2} - 4 x + 6 y + 2 z - 2 = 0

x, x^{2} y + 2 x y = 5 y^{3}

f, r^{2} = 2 f^{2} + 2 f

\frac{19 x ^{2}}{35} = 3

What are the solutions to the equation 6sqrt(5)*x^2-9x-3sqrt(5)=0 ?
The solutions to the equation 6sqrt(5)*x^2-9x-3sqrt(5)=0 are x=(sqrt(5))/2 ,x=-1/(sqrt(5))
Find the zeros of 6sqrt(5)*x^2-9x-3sqrt(5)=0
The zeros of 6sqrt(5)*x^2-9x-3sqrt(5)=0 are x=(sqrt(5))/2 ,x=-1/(sqrt(5))