What are the solutions to the equation solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0 ?

The solutions to the equation solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0 are

Find the zeros of solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0

The zeros of solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0 are

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solve for

x, p^{3} - (x^{2} + x y + y^{2}) \cdot p + x y (x + y) = 0

x = \frac{p y - y ^{2} + y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}, x = \frac{p y - y ^{2} - y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}; - p + y \neq = 0

Solution steps

p^{3} - (x^{2} + x y + y^{2}) p + x y (x + y) = 0

Expand

p^{3} - (x^{2} + x y + y^{2}) p + x y (x + y) : p^{3} - p x^{2} - p x y - p y^{2} + x^{2} y + x y^{2}

p^{3} - p x^{2} - p x y - p y^{2} + x^{2} y + x y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

(- p + y) x^{2} + (- p y + y^{2}) x + p^{3} - p y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - p y + y ^{2} ) \pm ( - p y + y ^{2} ) ^{2} - 4 ( - p + y ) ( p ^{3} - p y ^{2} )}{2 ( - p + y )}

Simplify

(- p y + y^{2})^{2} - 4 (- p + y) (p^{3} - p y^{2}) : y^{4} + 2 p y^{3} - 3 p^{2} y^{2} - 4 p^{3} y + 4 p^{4}

x_{1, 2} = \frac{- ( - p y + y ^{2} ) \pm y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}; - p + y \neq = 0

Separate the solutions

x_{1} = \frac{- ( - p y + y ^{2} ) + y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}, x_{2} = \frac{- ( - p y + y ^{2} ) - y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}

x = \frac{- ( - p y + y ^{2} ) + y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )} : \frac{p y - y ^{2} + y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}

x = \frac{- ( - p y + y ^{2} ) - y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )} : \frac{p y - y ^{2} - y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}

The solutions to the quadratic equation are:

x = \frac{p y - y ^{2} + y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}, x = \frac{p y - y ^{2} - y ^{4} + 2 p y ^{3} - 3 p ^{2} y ^{2} - 4 p ^{3} y + 4 p ^{4}}{2 ( - p + y )}; - p + y \neq = 0

\frac{5}{2} \cdot x + \frac{2}{3} \cdot x = \frac{95}{2} \cdot x^{2}

x, 4 x^{2} - 4 x y + y^{2} - 4 x - 8 y - 20 = 0

v^{1} c^{1} = v^{2} c^{2}

2 x^{2} - 5 x + 2 = 0, x - 2 < 0

x, x^{2} + (q - 2) x + 10 - q = 0

What are the solutions to the equation solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0 ?
The solutions to the equation solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0 are
Find the zeros of solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0
The zeros of solvefor x,p^3-(x^2+xy+y^2)*p+xy(x+y)=0 are