What are the solutions to the equation x^2+1= 41/25 ?

The solutions to the equation x^2+1= 41/25 are x= 4/5 ,x=-4/5

Find the zeros of x^2+1= 41/25

The zeros of x^2+1= 41/25 are x= 4/5 ,x=-4/5

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x^{2} + 1 = \frac{41}{25}

x = \frac{4}{5}, x = - \frac{4}{5}

Decimal Notation

x = 0.8, x = - 0.8

Solution steps

x^{2} + 1 = \frac{41}{25}

Move

1

to the right side

x^{2} = \frac{41}{25} - 1

Simplify

\frac{41}{25} - 1 : \frac{16}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{25}, x = - \frac{16}{25}

\frac{16}{25} = \frac{4}{5}

- \frac{16}{25} = - \frac{4}{5}

x = \frac{4}{5}, x = - \frac{4}{5}

5 \cdot x^{2} + 8 x - 45 = 0

t, m \cdot r u \cdot v s = 2 - 4 t + t^{2}

x^{2} - (3 + 1) \cdot x + 3 = 0

z, p^{2} z^{2} + q^{2} = 1

(3 x)^{2} = 9

What are the solutions to the equation x^2+1= 41/25 ?
The solutions to the equation x^2+1= 41/25 are x= 4/5 ,x=-4/5
Find the zeros of x^2+1= 41/25
The zeros of x^2+1= 41/25 are x= 4/5 ,x=-4/5