What are the solutions to the equation (1/3 x+4/3)^2=48 ?

The solutions to the equation (1/3 x+4/3)^2=48 are x=12sqrt(3)-4,x=-12sqrt(3)-4

Find the zeros of (1/3 x+4/3)^2=48

The zeros of (1/3 x+4/3)^2=48 are x=12sqrt(3)-4,x=-12sqrt(3)-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\frac{1}{3} x + \frac{4}{3})^{2} = 48

x = 123 - 4, x = - 123 - 4

Decimal Notation

x = 16.78460 \dots, x = - 24.78460 \dots

Solution steps

(\frac{1}{3} x + \frac{4}{3})^{2} = 48

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{1}{3} x + \frac{4}{3} = 48 : x = 123 - 4

Solve

\frac{1}{3} x + \frac{4}{3} = - 48 : x = - 123 - 4

The solutions to the quadratic equation are:

x = 123 - 4, x = - 123 - 4

m, m^{2} - 1 = n! + 1

100 = \frac{x ^{2}}{16}

m, m (m + 1) = n (n + 2)

x, z = 6 x^{2} - 3 x y - 2 y^{2}

x, (x + y + z)^{3} = x^{3} + y^{3} + z^{3}

What are the solutions to the equation (1/3 x+4/3)^2=48 ?
The solutions to the equation (1/3 x+4/3)^2=48 are x=12sqrt(3)-4,x=-12sqrt(3)-4
Find the zeros of (1/3 x+4/3)^2=48
The zeros of (1/3 x+4/3)^2=48 are x=12sqrt(3)-4,x=-12sqrt(3)-4