What are the solutions to the equation solvefor x,maxz=6x^1+4x^2 ?

The solutions to the equation solvefor x,maxz=6x^1+4x^2 are x=0,x=(maz-6)/4

Find the zeros of solvefor x,maxz=6x^1+4x^2

The zeros of solvefor x,maxz=6x^1+4x^2 are x=0,x=(maz-6)/4

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solve for

x, ma x z = 6 x^{1} + 4 x^{2}

x = 0, x = \frac{ma z - 6}{4}

Solution steps

ma x z = 6 x^{1} + 4 x^{2}

Switch sides

6 x^{1} + 4 x^{2} = ma x z

Move

ma x z

to the left side

6 x + 4 x^{2} - ma x z = 0

Factor

6 x + 4 x^{2} - ma x z : x (4 x - ma z + 6)

x (4 x - ma z + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x - ma z + 6 = 0

Solve

4 x - ma z + 6 = 0 : x = \frac{ma z - 6}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{ma z - 6}{4}

x, f (x - 2) = x^{2} + 15

x, (x - 2)^{2} + (y - 3)^{2} + (z + 4)^{2} = 0

(5) 63 \cdot x^{2} + 7 x = 3

4 (n - 2) 4 (n - 2) = 12

7.15 = (0.75 + 2 c) (0.3 + 2 c)

What are the solutions to the equation solvefor x,maxz=6x^1+4x^2 ?
The solutions to the equation solvefor x,maxz=6x^1+4x^2 are x=0,x=(maz-6)/4
Find the zeros of solvefor x,maxz=6x^1+4x^2
The zeros of solvefor x,maxz=6x^1+4x^2 are x=0,x=(maz-6)/4