What are the solutions to the equation -7x^2+6x-1=0 ?

The solutions to the equation -7x^2+6x-1=0 are x=(3-sqrt(2))/7 ,x=(3+sqrt(2))/7

Find the zeros of -7x^2+6x-1=0

The zeros of -7x^2+6x-1=0 are x=(3-sqrt(2))/7 ,x=(3+sqrt(2))/7

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- 7 x^{2} + 6 x - 1 = 0

x = \frac{3 - 2}{7}, x = \frac{3 + 2}{7}

Decimal Notation

x = 0.22654 \dots, x = 0.63060 \dots

Solution steps

- 7 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 7 ) ( - 1 )}{2 ( - 7 )}

6^{2} - 4 (- 7) (- 1) = 22

x_{1, 2} = \frac{- 6 \pm 2 2}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 2}{2 ( - 7 )}, x_{2} = \frac{- 6 - 2 2}{2 ( - 7 )}

x = \frac{- 6 + 2 2}{2 ( - 7 )} : \frac{3 - 2}{7}

x = \frac{- 6 - 2 2}{2 ( - 7 )} : \frac{3 + 2}{7}

The solutions to the quadratic equation are:

x = \frac{3 - 2}{7}, x = \frac{3 + 2}{7}

4 x^{2} + 4 x + 1 = 36

x, (x + y)^{2} = 64

4 - 11 x = 3 x^{2}

x, x^{2} + 9 y^{2} = 0

x, (x^{2} + y^{2}) (p^{2} + q^{2}) = 1

What are the solutions to the equation -7x^2+6x-1=0 ?
The solutions to the equation -7x^2+6x-1=0 are x=(3-sqrt(2))/7 ,x=(3+sqrt(2))/7
Find the zeros of -7x^2+6x-1=0
The zeros of -7x^2+6x-1=0 are x=(3-sqrt(2))/7 ,x=(3+sqrt(2))/7