What are the solutions to the equation solvefor x,x^2-y^2+x+y=0 ?

The solutions to the equation solvefor x,x^2-y^2+x+y=0 are x=-y,x=y-1

Find the zeros of solvefor x,x^2-y^2+x+y=0

The zeros of solvefor x,x^2-y^2+x+y=0 are x=-y,x=y-1

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solve for

x, x^{2} - y^{2} + x + y = 0

x = - y, x = y - 1

Solution steps

x^{2} - y^{2} + x + y = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + x - y^{2} + y = 0

Factor

x^{2} + x - y^{2} + y : (x + y) (x - y + 1)

(x + y) (x - y + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + y = 0 or x - y + 1 = 0

Solve

x + y = 0 : x = - y

Solve

x - y + 1 = 0 : x = y - 1

The solutions to the quadratic equation are:

x = - y, x = y - 1

- 34 x^{2} + 135 x - 449 = 0

\frac{3 x ^{2}}{5} = 6

(x + 2)^{3} = x^{3} - 4

t, \frac{( t ^{2} )}{( r ^{3} )} = k

7 - 3 x^{2} = 4

What are the solutions to the equation solvefor x,x^2-y^2+x+y=0 ?
The solutions to the equation solvefor x,x^2-y^2+x+y=0 are x=-y,x=y-1
Find the zeros of solvefor x,x^2-y^2+x+y=0
The zeros of solvefor x,x^2-y^2+x+y=0 are x=-y,x=y-1