What are the solutions to the equation solvefor x,s(x)=x(x-3) ?

The solutions to the equation solvefor x,s(x)=x(x-3) are x=0,x=s+3

Find the zeros of solvefor x,s(x)=x(x-3)

The zeros of solvefor x,s(x)=x(x-3) are x=0,x=s+3

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solve for

x, s (x) = x (x - 3)

x = 0, x = s + 3

Solution steps

s (x) = x (x - 3)

Move

x (x - 3)

to the left side

s x - x (x - 3) = 0

Factor

s x - x (x - 3) : x (s + 3 - x)

x (s + 3 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or s + 3 - x = 0

Solve

s + 3 - x = 0 : x = s + 3

The solutions to the quadratic equation are:

x = 0, x = s + 3

x^{2} - 125 = - 25

x, p = 36 x^{2} - 9 y^{2}

x, x^{2} + y^{2} + 2 x y - 2 x - 2 y - 15 = 0

(b - c) \cdot x^{2} + (c - a) x + (a - b) = 0

x, p = (x - 1) (x + 1) p (2)

What are the solutions to the equation solvefor x,s(x)=x(x-3) ?
The solutions to the equation solvefor x,s(x)=x(x-3) are x=0,x=s+3
Find the zeros of solvefor x,s(x)=x(x-3)
The zeros of solvefor x,s(x)=x(x-3) are x=0,x=s+3