What are the solutions to the equation (5(x^2+1))/(25)=10 ?

The solutions to the equation (5(x^2+1))/(25)=10 are x=7,x=-7

Find the zeros of (5(x^2+1))/(25)=10

The zeros of (5(x^2+1))/(25)=10 are x=7,x=-7

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\frac{5 ( x ^{2} + 1 )}{25} = 10

x = 7, x = - 7

Solution steps

\frac{5 ( x ^{2} + 1 )}{25} = 10

Multiply both sides by

25

5 (x^{2} + 1) = 250

Divide both sides by

5

x^{2} + 1 = 50

Move

1

to the right side

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

n (t) = 0.1 t^{2} - 4 t + 90

a, f + f^{2} = - a^{2}

z, r^{2} \cdot p^{2} \cdot z^{2} + 2 r p z + 1 = 0

x^{2} + 3 x - (a^{2} + a - 2) = 0

(2 a + 3) x^{2} - 3 (a + 1) x + 4 = 0

What are the solutions to the equation (5(x^2+1))/(25)=10 ?
The solutions to the equation (5(x^2+1))/(25)=10 are x=7,x=-7
Find the zeros of (5(x^2+1))/(25)=10
The zeros of (5(x^2+1))/(25)=10 are x=7,x=-7