What are the solutions to the equation x^1+x^2=5 ?

The solutions to the equation x^1+x^2=5 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2

Find the zeros of x^1+x^2=5

The zeros of x^1+x^2=5 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{1} + x^{2} = 5

x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

Decimal Notation

x = 1.79128 \dots, x = - 2.79128 \dots

Solution steps

x^{1} + x^{2} = 5

Refine

x + x^{2} = 5

Move

5

to the left side

x + x^{2} - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 5) = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 \cdot 1}, x_{2} = \frac{- 1 - 21}{2 \cdot 1}

x = \frac{- 1 + 21}{2 \cdot 1} : \frac{- 1 + 21}{2}

x = \frac{- 1 - 21}{2 \cdot 1} : \frac{- 1 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 21}{2}, x = \frac{- 1 - 21}{2}

x, x^{2} - 4 y^{2} - z = 0

x, y^{n} = 2 x^{2}

(u + 1) (u^{2} - 2) = (u + 3)^{3}

x^{2} - 4 a^{2} = 3 b (2 x - 3 b)

4.9 x^{2} = 19.6

What are the solutions to the equation x^1+x^2=5 ?
The solutions to the equation x^1+x^2=5 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2
Find the zeros of x^1+x^2=5
The zeros of x^1+x^2=5 are x=(-1+sqrt(21))/2 ,x=(-1-sqrt(21))/2