What are the solutions to the equation (x+3}{4-3}=\frac{(x+5)(x-2))/3 ?

The solutions to the equation (x+3}{4-3}=\frac{(x+5)(x-2))/3 are x=sqrt(19),x=-sqrt(19)

Find the zeros of (x+3}{4-3}=\frac{(x+5)(x-2))/3

The zeros of (x+3}{4-3}=\frac{(x+5)(x-2))/3 are x=sqrt(19),x=-sqrt(19)

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\frac{x + 3}{4 - 3} = \frac{( x + 5 ) ( x - 2 )}{3}

x = 19, x = - 19

Decimal Notation

x = 4.35889 \dots, x = - 4.35889 \dots

Solution steps

\frac{x + 3}{4 - 3} = \frac{( x + 5 ) ( x - 2 )}{3}

Expand

\frac{x + 3}{4 - 3} : x + 3

Expand

\frac{( x + 5 ) ( x - 2 )}{3} : \frac{x ^{2}}{3} + x - \frac{10}{3}

x + 3 = \frac{x ^{2}}{3} + x - \frac{10}{3}

Switch sides

\frac{x ^{2}}{3} + x - \frac{10}{3} = x + 3

Move

\frac{10}{3}

to the right side

\frac{x ^{2}}{3} + x = x + 3 + \frac{10}{3}

Move

x

to the left side

\frac{x ^{2}}{3} = 3 + \frac{10}{3}

Simplify

3 + \frac{10}{3} : \frac{19}{3}

\frac{x ^{2}}{3} = \frac{19}{3}

Multiply both sides by

3

x^{2} = 19

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 19, x = - 19

\frac{x ^{2} - ( 17 x )}{4 + 1} = 0

2 p^{2} + k^{3} = 15

(x) = - 5 (x + 20) \cdot (x - 80)

x, x^{2} + y^{2} + x y = 192

(16 x)^{2} + (9 x)^{2} = 4 3^{2}

What are the solutions to the equation (x+3}{4-3}=\frac{(x+5)(x-2))/3 ?
The solutions to the equation (x+3}{4-3}=\frac{(x+5)(x-2))/3 are x=sqrt(19),x=-sqrt(19)
Find the zeros of (x+3}{4-3}=\frac{(x+5)(x-2))/3
The zeros of (x+3}{4-3}=\frac{(x+5)(x-2))/3 are x=sqrt(19),x=-sqrt(19)