What are the solutions to the equation x^2=a^2+b^2 ?

The solutions to the equation x^2=a^2+b^2 are x=sqrt(a^2+b^2),x=-sqrt(a^2+b^2)

Find the zeros of x^2=a^2+b^2

The zeros of x^2=a^2+b^2 are x=sqrt(a^2+b^2),x=-sqrt(a^2+b^2)

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x^{2} = a^{2} + b^{2}

x = a^{2} + b^{2}, x = - a^{2} + b^{2}

Solution steps

x^{2} = a^{2} + b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = a^{2} + b^{2}, x = - a^{2} + b^{2}

e = 0.5 + 2.7 \cdot 1 0^{- 2} t + 2.8 \cdot 1 0^{- 5} t^{2}

(\frac{5}{3})^{2} x \cdot (\frac{3}{5})^{9} x = 1

2 2 1^{2} + 4^{2} = c^{2}

x, x^{2} - 2 x + y^{2} - 4 y + 5 = 0

x, (2 x - 1) (3 x + q + 2) = 3 x + q + 2

What are the solutions to the equation x^2=a^2+b^2 ?
The solutions to the equation x^2=a^2+b^2 are x=sqrt(a^2+b^2),x=-sqrt(a^2+b^2)
Find the zeros of x^2=a^2+b^2
The zeros of x^2=a^2+b^2 are x=sqrt(a^2+b^2),x=-sqrt(a^2+b^2)