What are the solutions to the equation 3x^2+14x-49=0 ?

The solutions to the equation 3x^2+14x-49=0 are x= 7/3 ,x=-7

Find the zeros of 3x^2+14x-49=0

The zeros of 3x^2+14x-49=0 are x= 7/3 ,x=-7

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3 x^{2} + 14 x - 49 = 0

x = \frac{7}{3}, x = - 7

Decimal Notation

x = 2.33333 \dots, x = - 7

Solution steps

3 x^{2} + 14 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 ( - 49 )}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 (- 49) = 28

x_{1, 2} = \frac{- 14 \pm 28}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 28}{2 \cdot 3}, x_{2} = \frac{- 14 - 28}{2 \cdot 3}

x = \frac{- 14 + 28}{2 \cdot 3} : \frac{7}{3}

x = \frac{- 14 - 28}{2 \cdot 3} : - 7

The solutions to the quadratic equation are:

x = \frac{7}{3}, x = - 7

x^{2} (4 x^{- \frac{1}{2}})^{2}

x^{2} - 11 x y - 26 y^{2}

\frac{( 2 T + 5 ) ( 3 T - 1 )}{3} + \frac{T ^{2} + 5}{2} = \frac{7 T - 5}{6} + 1

8. 5^{2}

- 5 (x - 2) - (x + 2) = 50

What are the solutions to the equation 3x^2+14x-49=0 ?
The solutions to the equation 3x^2+14x-49=0 are x= 7/3 ,x=-7
Find the zeros of 3x^2+14x-49=0
The zeros of 3x^2+14x-49=0 are x= 7/3 ,x=-7