What are the solutions to the equation 2((x+1)/3)^2= 1/2 ?

The solutions to the equation 2((x+1)/3)^2= 1/2 are x= 1/2 ,x=-5/2

Find the zeros of 2((x+1)/3)^2= 1/2

The zeros of 2((x+1)/3)^2= 1/2 are x= 1/2 ,x=-5/2

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2 (\frac{x + 1}{3})^{2} = \frac{1}{2}

x = \frac{1}{2}, x = - \frac{5}{2}

Decimal Notation

x = 0.5, x = - 2.5

Solution steps

2 (\frac{x + 1}{3})^{2} = \frac{1}{2}

Divide both sides by

2

(\frac{x + 1}{3})^{2} = \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{x + 1}{3} = \frac{1}{4} : x = \frac{1}{2}

Solve

\frac{x + 1}{3} = - \frac{1}{4} : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{5}{2}

1 \cdot 1 0^{5} [6.666 u^{2} - 3.333 (1.2)] = 6 \cdot 1 0^{5}

(\frac{43}{42.5}) n^{2} - n^{2} = 3

b (x) = - 9 x - 6 + 4 x^{2}

x, x^{2} + 4 x y - y^{2} + 3 x - 8 y + 2 = 0

4.9 t^{2} + 294 t - 2450 = 0

What are the solutions to the equation 2((x+1)/3)^2= 1/2 ?
The solutions to the equation 2((x+1)/3)^2= 1/2 are x= 1/2 ,x=-5/2
Find the zeros of 2((x+1)/3)^2= 1/2
The zeros of 2((x+1)/3)^2= 1/2 are x= 1/2 ,x=-5/2