What are the solutions to the equation 12x^2+13x+3=0 ?

The solutions to the equation 12x^2+13x+3=0 are x=-1/3 ,x=-3/4

Find the zeros of 12x^2+13x+3=0

The zeros of 12x^2+13x+3=0 are x=-1/3 ,x=-3/4

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12 x^{2} + 13 x + 3 = 0

x = - \frac{1}{3}, x = - \frac{3}{4}

Decimal Notation

x = - 0.33333 \dots, x = - 0.75

Solution steps

12 x^{2} + 13 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

1 3^{2} - 4 \cdot 12 \cdot 3 = 5

x_{1, 2} = \frac{- 13 \pm 5}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 13 + 5}{2 \cdot 12}, x_{2} = \frac{- 13 - 5}{2 \cdot 12}

x = \frac{- 13 + 5}{2 \cdot 12} : - \frac{1}{3}

x = \frac{- 13 - 5}{2 \cdot 12} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = - \frac{3}{4}

[x^{2} - 1] = - 1

x, (y^{1})^{1} - 5 y^{1} + 6 y = e^{3} x - x^{2}

x_{x}^{2} - 6 = 0

x, 2 f + 3 f (- x) = x^{2} + x + 1

\frac{( x ^{2} - 4 )}{3} = \frac{( x - 3 )}{2}

What are the solutions to the equation 12x^2+13x+3=0 ?
The solutions to the equation 12x^2+13x+3=0 are x=-1/3 ,x=-3/4
Find the zeros of 12x^2+13x+3=0
The zeros of 12x^2+13x+3=0 are x=-1/3 ,x=-3/4