What are the solutions to the equation solvefor x,1^2+x^2=c*p^2 ?

The solutions to the equation solvefor x,1^2+x^2=c*p^2 are x=sqrt(cp^2-1),x=-sqrt(cp^2-1)

Find the zeros of solvefor x,1^2+x^2=c*p^2

The zeros of solvefor x,1^2+x^2=c*p^2 are x=sqrt(cp^2-1),x=-sqrt(cp^2-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, 1^{2} + x^{2} = c \cdot p^{2}

x = c p^{2} - 1, x = - c p^{2} - 1

Solution steps

1^{2} + x^{2} = c p^{2}

Move

1^{2}

to the right side

x^{2} = c p^{2} - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = c p^{2} - 1, x = - c p^{2} - 1

x, 5 x^{2} - 7 x y - 3 y^{2} = 0

x, f (x + 1) = (x + 1)^{2} - 1

x, x^{2} + k (4 x + k - 1) + 2 = 0

150 = 0.0216 d^{2} + 0.0216 (\frac{d + 8}{16})^{2}

x^{2} = x + 1, x^{4}

What are the solutions to the equation solvefor x,1^2+x^2=c*p^2 ?
The solutions to the equation solvefor x,1^2+x^2=c*p^2 are x=sqrt(cp^2-1),x=-sqrt(cp^2-1)
Find the zeros of solvefor x,1^2+x^2=c*p^2
The zeros of solvefor x,1^2+x^2=c*p^2 are x=sqrt(cp^2-1),x=-sqrt(cp^2-1)