What are the solutions to the equation (x-5)(2x+5)=0 ?

The solutions to the equation (x-5)(2x+5)=0 are x=5,x=-5/2

Find the zeros of (x-5)(2x+5)=0

The zeros of (x-5)(2x+5)=0 are x=5,x=-5/2

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(x - 5) (2 x + 5) = 0

x = 5, x = - \frac{5}{2}

Decimal Notation

x = 5, x = - 2.5

Solution steps

(x - 5) (2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or 2 x + 5 = 0

Solve

x - 5 = 0 : x = 5

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

The solutions to the quadratic equation are:

x = 5, x = - \frac{5}{2}

x^{2} + 9 x - 3 b = 0

x, 428 x \frac{x}{y} = 12.24

x, p^{2} - y^{2} \cdot q = x^{2} - y^{2}

4 z^{2} + 4 (m - 1) \cdot z + m^{2} - 3 m = 0

(k + 1) x^{2} - 2 (k - 1) x + 1 = 0

What are the solutions to the equation (x-5)(2x+5)=0 ?
The solutions to the equation (x-5)(2x+5)=0 are x=5,x=-5/2
Find the zeros of (x-5)(2x+5)=0
The zeros of (x-5)(2x+5)=0 are x=5,x=-5/2