What are the solutions to the equation sqrt(2)*x^2+4x+2sqrt(2)=0 ?

The solutions to the equation sqrt(2)*x^2+4x+2sqrt(2)=0 are x=-sqrt(2)

Find the zeros of sqrt(2)*x^2+4x+2sqrt(2)=0

The zeros of sqrt(2)*x^2+4x+2sqrt(2)=0 are x=-sqrt(2)

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2 \cdot x^{2} + 4 x + 22 = 0

x = - 2

Decimal Notation

x = - 1.41421 \dots

Solution steps

2 x^{2} + 4 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 2 \cdot 2 2}{2 2}

4^{2} - 42 \cdot 22 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 2}

x = \frac{- 4}{2 2}

\frac{- 4}{2 2} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

u, u^{2} + v^{2} = r^{2}

x, (x + y) = x^{2} + 2 x y + y^{2}

x^{2} - 0.5 x + 0.04 = 0

x^{2} - x - 45 = 0

136 y^{2} + 36 y - 681 = 0

What are the solutions to the equation sqrt(2)*x^2+4x+2sqrt(2)=0 ?
The solutions to the equation sqrt(2)*x^2+4x+2sqrt(2)=0 are x=-sqrt(2)
Find the zeros of sqrt(2)*x^2+4x+2sqrt(2)=0
The zeros of sqrt(2)*x^2+4x+2sqrt(2)=0 are x=-sqrt(2)