What are the solutions to the equation (x^2)/(2+2)=20 ?

The solutions to the equation (x^2)/(2+2)=20 are x=4sqrt(5),x=-4sqrt(5)

Find the zeros of (x^2)/(2+2)=20

The zeros of (x^2)/(2+2)=20 are x=4sqrt(5),x=-4sqrt(5)

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\frac{x ^{2}}{2 + 2} = 20

x = 45, x = - 45

Decimal Notation

x = 8.94427 \dots, x = - 8.94427 \dots

Solution steps

\frac{x ^{2}}{2 + 2} = 20

Multiply both sides by

2 + 2

x^{2} = 80

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 80, x = - 80

80 = 45

- 80 = - 45

x = 45, x = - 45

\frac{0.44 x ( x + x \cdot 5 - \frac{23}{55} ) + 3}{14 \cdot 2.24} = 1

48 x^{2} - 13 x - 1 = 0

(k^{2} + 3) \cdot x^{2} + (k^{3} + k + 1) \cdot x + 2 k + 2 = 0

(a + b) 2 x^{2} + 6 (a^{2} - b^{2}) x + 9 (a - b) 2 = 0

x^{2} + (m - 1) x + (m + 2) = 0

What are the solutions to the equation (x^2)/(2+2)=20 ?
The solutions to the equation (x^2)/(2+2)=20 are x=4sqrt(5),x=-4sqrt(5)
Find the zeros of (x^2)/(2+2)=20
The zeros of (x^2)/(2+2)=20 are x=4sqrt(5),x=-4sqrt(5)