What are the solutions to the equation (3x^2-4x)/6 =20x ?

The solutions to the equation (3x^2-4x)/6 =20x are x= 124/3 ,x=0

Find the zeros of (3x^2-4x)/6 =20x

The zeros of (3x^2-4x)/6 =20x are x= 124/3 ,x=0

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\frac{3 x ^{2} - 4 x}{6} = 20 x

x = \frac{124}{3}, x = 0

Decimal Notation

x = 41.33333 \dots, x = 0

Solution steps

\frac{3 x ^{2} - 4 x}{6} = 20 x

Multiply both sides by

6

3 x^{2} - 4 x = 120 x

Move

120 x

to the left side

3 x^{2} - 124 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 124 ) \pm ( - 124 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 124)^{2} - 4 \cdot 3 \cdot 0 = 124

x_{1, 2} = \frac{- ( - 124 ) \pm 124}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 124 ) + 124}{2 \cdot 3}, x_{2} = \frac{- ( - 124 ) - 124}{2 \cdot 3}

x = \frac{- ( - 124 ) + 124}{2 \cdot 3} : \frac{124}{3}

x = \frac{- ( - 124 ) - 124}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = \frac{124}{3}, x = 0

\frac{x ^{2} - x}{12} = 1

a^{12} x + 4 x = - 3 x^{2} + x - 5

3 x^{1} - 2 x^{2} = 4

3 x^{2} - (7 - k) \cdot x + 9 = 0

(2 m - 3) x^{2} - 2 x + 1 = 0

What are the solutions to the equation (3x^2-4x)/6 =20x ?
The solutions to the equation (3x^2-4x)/6 =20x are x= 124/3 ,x=0
Find the zeros of (3x^2-4x)/6 =20x
The zeros of (3x^2-4x)/6 =20x are x= 124/3 ,x=0