What is 1/x+1/(x+1)< 2/(x+5) ?

The solution to 1/x+1/(x+1)< 2/(x+5) is -5<x<-1\lor-5/9 <x<0

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1/x+1/(x+1)< 2/(x+5)

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 5}

- 5 < x < - 1 or - \frac{5}{9} < x < 0

Interval Notation

(- 5, - 1) \cup (- \frac{5}{9}, 0)

Decimal Notation

- 5 < x < - 1 or - 0.55555 \dots < x < 0

Solution steps

\frac{1}{x} + \frac{1}{x + 1} < \frac{2}{x + 5}

Rewrite in standard form

\frac{9 x + 5}{x ( x + 1 ) ( x + 5 )} < 0

Identify the intervals

- 5 < x < - 1 or - \frac{5}{9} < x < 0

\frac{\frac{0.51}{204.22}}{0.0136}

x^{2} - 5 = 0

- (\frac{2}{5})^{3}

5 (u + 1) = 8 u + 26

\frac{3}{2} 6 - 3 + \frac{5}{3} 3

What is 1/x+1/(x+1)< 2/(x+5) ?
The solution to 1/x+1/(x+1)< 2/(x+5) is -5<x<-1\lor-5/9 <x<0