What are the solutions to the equation m^2-14m-1=0 ?

The solutions to the equation m^2-14m-1=0 are m=7+5sqrt(2),m=7-5sqrt(2)

Find the zeros of m^2-14m-1=0

The zeros of m^2-14m-1=0 are m=7+5sqrt(2),m=7-5sqrt(2)

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m^{2} - 14 m - 1 = 0

m = 7 + 52, m = 7 - 52

Decimal Notation

m = 14.07106 \dots, m = - 0.07106 \dots

Solution steps

m^{2} - 14 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 1) = 102

m_{1, 2} = \frac{- ( - 14 ) \pm 10 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 14 ) + 10 2}{2 \cdot 1}, m_{2} = \frac{- ( - 14 ) - 10 2}{2 \cdot 1}

m = \frac{- ( - 14 ) + 10 2}{2 \cdot 1} : 7 + 52

m = \frac{- ( - 14 ) - 10 2}{2 \cdot 1} : 7 - 52

The solutions to the quadratic equation are:

m = 7 + 52, m = 7 - 52

c^{2} + 4 = 4 c

0.5 x (x + 1) = - 1

d^{0.4} x (x - 1) - 3 (x^{2} - 5) - x^{2} = (x - 3) - (x + 4)

x, f (x + h) = x^{2} + h

t, x = v_{0} \cdot t + \frac{1}{2} \cdot a \cdot t^{2}

What are the solutions to the equation m^2-14m-1=0 ?
The solutions to the equation m^2-14m-1=0 are m=7+5sqrt(2),m=7-5sqrt(2)
Find the zeros of m^2-14m-1=0
The zeros of m^2-14m-1=0 are m=7+5sqrt(2),m=7-5sqrt(2)