What are the solutions to the equation y(y+5)=14 ?

The solutions to the equation y(y+5)=14 are y=2,y=-7

Find the zeros of y(y+5)=14

The zeros of y(y+5)=14 are y=2,y=-7

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y (y + 5) = 14

y = 2, y = - 7

Solution steps

y (y + 5) = 14

Expand

y (y + 5) : y^{2} + 5 y

y^{2} + 5 y = 14

Move

14

to the left side

y^{2} + 5 y - 14 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 14) = 9

y_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 9}{2 \cdot 1}, y_{2} = \frac{- 5 - 9}{2 \cdot 1}

y = \frac{- 5 + 9}{2 \cdot 1} : 2

y = \frac{- 5 - 9}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

y = 2, y = - 7

2 x^{2} - 5 x + (3 - k) = 0

x, 4 x^{2} + 6 x y + 4 y^{2} = 1

x^{2} - x (6 - 1) - 6 = 0

x, 2 x^{2} + p^{2} = (q - x)^{2}

a \cdot x^{2} - 8 x + 4 = 0

What are the solutions to the equation y(y+5)=14 ?
The solutions to the equation y(y+5)=14 are y=2,y=-7
Find the zeros of y(y+5)=14
The zeros of y(y+5)=14 are y=2,y=-7