What are the solutions to the equation x^2=4 x/5+1/5 ?

The solutions to the equation x^2=4 x/5+1/5 are x=1,x=-1/5

Find the zeros of x^2=4 x/5+1/5

The zeros of x^2=4 x/5+1/5 are x=1,x=-1/5

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x^{2} = 4 \frac{x}{5} + \frac{1}{5}

x = 1, x = - \frac{1}{5}

Decimal Notation

x = 1, x = - 0.2

Solution steps

x^{2} = 4 \cdot \frac{x}{5} + \frac{1}{5}

Multiply both sides by

5

5 x^{2} = 4 x + 1

Move

1

to the left side

5 x^{2} - 1 = 4 x

Move

4 x

to the left side

5 x^{2} - 1 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 1) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 5}

x = \frac{- ( - 4 ) + 6}{2 \cdot 5} : 1

x = \frac{- ( - 4 ) - 6}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{5}

(m - 1) \cdot x^{2} - 2 (m - 1) x + 1 = 0

x, y^{2} = \frac{( 9 x ^{2} )}{36}

x, w = x^{2} - 25

x (5 x - 7) = - 2

a, x = (a - b)^{2}

What are the solutions to the equation x^2=4 x/5+1/5 ?
The solutions to the equation x^2=4 x/5+1/5 are x=1,x=-1/5
Find the zeros of x^2=4 x/5+1/5
The zeros of x^2=4 x/5+1/5 are x=1,x=-1/5