What are the solutions to the equation ((2x+3)/4)^2= 49/25 ?

The solutions to the equation ((2x+3)/4)^2= 49/25 are x= 13/10 ,x=-43/10

Find the zeros of ((2x+3)/4)^2= 49/25

The zeros of ((2x+3)/4)^2= 49/25 are x= 13/10 ,x=-43/10

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(\frac{2 x + 3}{4})^{2} = \frac{49}{25}

x = \frac{13}{10}, x = - \frac{43}{10}

Decimal Notation

x = 1.3, x = - 4.3

Solution steps

(\frac{2 x + 3}{4})^{2} = \frac{49}{25}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{2 x + 3}{4} = \frac{49}{25} : x = \frac{13}{10}

Solve

\frac{2 x + 3}{4} = - \frac{49}{25} : x = - \frac{43}{10}

The solutions to the quadratic equation are:

x = \frac{13}{10}, x = - \frac{43}{10}

6 x (2 + x) = 45

x, x^{2} + x y + y^{2} = 100

x^{2} - \frac{2}{5} \cdot x + \frac{1}{25} = 0

x, f (x^{2}) = x + 3

452.16 = 3.14 r^{2}

What are the solutions to the equation ((2x+3)/4)^2= 49/25 ?
The solutions to the equation ((2x+3)/4)^2= 49/25 are x= 13/10 ,x=-43/10
Find the zeros of ((2x+3)/4)^2= 49/25
The zeros of ((2x+3)/4)^2= 49/25 are x= 13/10 ,x=-43/10