What are the solutions to the equation solvefor x,x^2-2^y=23 ?

The solutions to the equation solvefor x,x^2-2^y=23 are x=sqrt(23+2^y),x=-sqrt(23+2^y)

Find the zeros of solvefor x,x^2-2^y=23

The zeros of solvefor x,x^2-2^y=23 are x=sqrt(23+2^y),x=-sqrt(23+2^y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} - 2^{y} = 23

x = 23 + 2^{y}, x = - 23 + 2^{y}

Solution steps

x^{2} - 2^{y} = 23

Move

2^{y}

to the right side

x^{2} = 23 + 2^{y}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 23 + 2^{y}, x = - 23 + 2^{y}

x, \frac{x}{2} - 3 + 3 x^{2} + x - 6 = (f + g) (x)

x, x \cdot y^{2} + x^{2} \cdot y + 1 = 0

1.5 x^{2} + 2 x = 10

x, f = x^{2} - 2 x + k

y, (d - y)^{2} + (d + y)^{2} = 0

What are the solutions to the equation solvefor x,x^2-2^y=23 ?
The solutions to the equation solvefor x,x^2-2^y=23 are x=sqrt(23+2^y),x=-sqrt(23+2^y)
Find the zeros of solvefor x,x^2-2^y=23
The zeros of solvefor x,x^2-2^y=23 are x=sqrt(23+2^y),x=-sqrt(23+2^y)