What are the solutions to the equation solvefor x,x(x+4y)-3=0 ?

The solutions to the equation solvefor x,x(x+4y)-3=0 are x=-2y+sqrt(4y^2+3),x=-2y-sqrt(4y^2+3)

Find the zeros of solvefor x,x(x+4y)-3=0

The zeros of solvefor x,x(x+4y)-3=0 are x=-2y+sqrt(4y^2+3),x=-2y-sqrt(4y^2+3)

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solve for

x, x (x + 4 y) - 3 = 0

x = - 2 y + 4 y^{2} + 3, x = - 2 y - 4 y^{2} + 3

Solution steps

x (x + 4 y) - 3 = 0

Expand

x (x + 4 y) - 3 : x^{2} + 4 x y - 3

x^{2} + 4 x y - 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 y x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 y \pm ( 4 y ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

Simplify

(4 y)^{2} - 4 \cdot 1 \cdot (- 3) : 2 4 y^{2} + 3

x_{1, 2} = \frac{- 4 y \pm 2 4 y ^{2} + 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 y + 2 4 y ^{2} + 3}{2 \cdot 1}, x_{2} = \frac{- 4 y - 2 4 y ^{2} + 3}{2 \cdot 1}

x = \frac{- 4 y + 2 4 y ^{2} + 3}{2 \cdot 1} : - 2 y + 4 y^{2} + 3

x = \frac{- 4 y - 2 4 y ^{2} + 3}{2 \cdot 1} : - 2 y - 4 y^{2} + 3

The solutions to the quadratic equation are:

x = - 2 y + 4 y^{2} + 3, x = - 2 y - 4 y^{2} + 3

y, x = \frac{1}{4} p y^{2}

x^{2} + 15 x - 5400 = 0

x^{2} + 2 n + 4 = 0

17 a^{2} - 22 a + 10 = 10 a^{2} + 2 a + 7

a^{2} b^{2} x^{2} - (a^{2} + b^{2}) x + 1 = 0

What are the solutions to the equation solvefor x,x(x+4y)-3=0 ?
The solutions to the equation solvefor x,x(x+4y)-3=0 are x=-2y+sqrt(4y^2+3),x=-2y-sqrt(4y^2+3)
Find the zeros of solvefor x,x(x+4y)-3=0
The zeros of solvefor x,x(x+4y)-3=0 are x=-2y+sqrt(4y^2+3),x=-2y-sqrt(4y^2+3)