What are the solutions to the equation a=3x^2-9x ?

The solutions to the equation a=3x^2-9x are x=(9+sqrt(81+12a))/6 ,x=(9-sqrt(81+12a))/6

Find the zeros of a=3x^2-9x

The zeros of a=3x^2-9x are x=(9+sqrt(81+12a))/6 ,x=(9-sqrt(81+12a))/6

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a = 3 x^{2} - 9 x

x = \frac{9 + 81 + 12 a}{6}, x = \frac{9 - 81 + 12 a}{6}

Solution steps

a = 3 x^{2} - 9 x

Switch sides

3 x^{2} - 9 x = a

Move

a

to the left side

3 x^{2} - 9 x - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 ( - a )}{2 \cdot 3}

Simplify

(- 9)^{2} - 4 \cdot 3 (- a) : 81 + 12 a

x_{1, 2} = \frac{- ( - 9 ) \pm 81 + 12 a}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 81 + 12 a}{2 \cdot 3}, x_{2} = \frac{- ( - 9 ) - 81 + 12 a}{2 \cdot 3}

x = \frac{- ( - 9 ) + 81 + 12 a}{2 \cdot 3} : \frac{9 + 81 + 12 a}{6}

x = \frac{- ( - 9 ) - 81 + 12 a}{2 \cdot 3} : \frac{9 - 81 + 12 a}{6}

The solutions to the quadratic equation are:

x = \frac{9 + 81 + 12 a}{6}, x = \frac{9 - 81 + 12 a}{6}

x, z = x^{2} - 8 x y + 5 y + 7

a = 3 r^{2}

x, 2 x^{2} - 5 x y + 3 y^{2} + 7 x - 10 y + 3 = 0

x, x^{2} + 3 x + 1 = 5^{y}

x, x^{2} + y^{2} + z^{3} = 6

What are the solutions to the equation a=3x^2-9x ?
The solutions to the equation a=3x^2-9x are x=(9+sqrt(81+12a))/6 ,x=(9-sqrt(81+12a))/6
Find the zeros of a=3x^2-9x
The zeros of a=3x^2-9x are x=(9+sqrt(81+12a))/6 ,x=(9-sqrt(81+12a))/6