What are the solutions to the equation sqrt(3)x^2-4sqrt(3)x-6=0 ?

The solutions to the equation sqrt(3)x^2-4sqrt(3)x-6=0 are x=3+sqrt(3),x=1-sqrt(3)

Find the zeros of sqrt(3)x^2-4sqrt(3)x-6=0

The zeros of sqrt(3)x^2-4sqrt(3)x-6=0 are x=3+sqrt(3),x=1-sqrt(3)

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3 x^{2} - 43 x - 6 = 0

x = 3 + 3, x = 1 - 3

Decimal Notation

x = 4.73205 \dots, x = - 0.73205 \dots

Solution steps

3 x^{2} - 43 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 3 ) \pm ( - 4 3 ) ^{2} - 4 3 ( - 6 )}{2 3}

(- 43)^{2} - 43 (- 6) = 23 + 6

x_{1, 2} = \frac{- ( - 4 3 ) \pm ( 2 3 + 6 )}{2 3}

Separate the solutions

x_{1} = \frac{- ( - 4 3 ) + 2 3 + 6}{2 3}, x_{2} = \frac{- ( - 4 3 ) - ( 2 3 + 6 )}{2 3}

x = \frac{- ( - 4 3 ) + 2 3 + 6}{2 3} : 3 + 3

x = \frac{- ( - 4 3 ) - ( 2 3 + 6 )}{2 3} : 1 - 3

The solutions to the quadratic equation are:

x = 3 + 3, x = 1 - 3

2 x^{2} - 16 x = 12 x + 48

(\frac{5 x - 1}{3})^{2} = \frac{4}{9}

x^{2} + 2 (m + 1) x - 3 m (m - 2) = 0

x, f = f (x^{2}) - 2 f (1)

x, x^{2} + y^{2} + z^{2} - 25 = 0

What are the solutions to the equation sqrt(3)x^2-4sqrt(3)x-6=0 ?
The solutions to the equation sqrt(3)x^2-4sqrt(3)x-6=0 are x=3+sqrt(3),x=1-sqrt(3)
Find the zeros of sqrt(3)x^2-4sqrt(3)x-6=0
The zeros of sqrt(3)x^2-4sqrt(3)x-6=0 are x=3+sqrt(3),x=1-sqrt(3)