What are the solutions to the equation solvefor x,(y-3x)(x-8y)=0 ?

The solutions to the equation solvefor x,(y-3x)(x-8y)=0 are x= y/3 ,x=8y

Find the zeros of solvefor x,(y-3x)(x-8y)=0

The zeros of solvefor x,(y-3x)(x-8y)=0 are x= y/3 ,x=8y

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solve for

x, (y - 3 x) (x - 8 y) = 0

x = \frac{y}{3}, x = 8 y

Solution steps

(y - 3 x) (x - 8 y) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y - 3 x = 0 or x - 8 y = 0

Solve

y - 3 x = 0 : x = \frac{y}{3}

Solve

x - 8 y = 0 : x = 8 y

The solutions to the quadratic equation are:

x = \frac{y}{3}, x = 8 y

x, z = 3 \cdot x^{2} - x \cdot y^{2}

l, a = l^{2}

x, x y + x^{2} y^{2} = c

t, q \cdot 3 (d) \cdot v = (\frac{( t ^{2} )}{4} + 15 - 3) \cdot \frac{m}{s}

x^{2} - 1.21 = 0

What are the solutions to the equation solvefor x,(y-3x)(x-8y)=0 ?
The solutions to the equation solvefor x,(y-3x)(x-8y)=0 are x= y/3 ,x=8y
Find the zeros of solvefor x,(y-3x)(x-8y)=0
The zeros of solvefor x,(y-3x)(x-8y)=0 are x= y/3 ,x=8y