What are the solutions to the equation (q)=3q^2+5q+10 ?

The solutions to the equation (q)=3q^2+5q+10 are q=-2/3+i(sqrt(26))/3 ,q=-2/3-i(sqrt(26))/3

Find the zeros of (q)=3q^2+5q+10

The zeros of (q)=3q^2+5q+10 are q=-2/3+i(sqrt(26))/3 ,q=-2/3-i(sqrt(26))/3

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(q) = 3 q^{2} + 5 q + 10

q = - \frac{2}{3} + i \frac{26}{3}, q = - \frac{2}{3} - i \frac{26}{3}

Solution steps

(q) = 3 q^{2} + 5 q + 10

Refine

q = 3 q^{2} + 5 q + 10

Switch sides

3 q^{2} + 5 q + 10 = q

Move

q

to the left side

3 q^{2} + 4 q + 10 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 10}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 10 : 226 i

q_{1, 2} = \frac{- 4 \pm 2 26 i}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- 4 + 2 26 i}{2 \cdot 3}, q_{2} = \frac{- 4 - 2 26 i}{2 \cdot 3}

q = \frac{- 4 + 2 26 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{26}{3}

q = \frac{- 4 - 2 26 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{26}{3}

The solutions to the quadratic equation are:

q = - \frac{2}{3} + i \frac{26}{3}, q = - \frac{2}{3} - i \frac{26}{3}

4.9 t^{2} + 12 t - 171 = 0

16 x^{2} - 102 + 44 = 0

z^{2} - 2 z = - 5

x^{2} = 0.0081

x, 3 x 7 - 4 x^{2} y + x y^{3} = 25

What are the solutions to the equation (q)=3q^2+5q+10 ?
The solutions to the equation (q)=3q^2+5q+10 are q=-2/3+i(sqrt(26))/3 ,q=-2/3-i(sqrt(26))/3
Find the zeros of (q)=3q^2+5q+10
The zeros of (q)=3q^2+5q+10 are q=-2/3+i(sqrt(26))/3 ,q=-2/3-i(sqrt(26))/3